70
edits
Talk:Catch rate: Difference between revisions
→rounding of a
Dragonfree (talk | contribs) |
|||
| Line 467: | Line 467: | ||
::::So, in my example, for a would equal 2.5=(2+2048/4096), or if using the current catch rate, a=3*1.5/3=1.5=(1+2048/4096)[[User:Zombiedude347|Zombiedude347]] ([[User talk:Zombiedude347|talk]]) 15:46, 29 December 2014 (UTC) | ::::So, in my example, for a would equal 2.5=(2+2048/4096), or if using the current catch rate, a=3*1.5/3=1.5=(1+2048/4096)[[User:Zombiedude347|Zombiedude347]] ([[User talk:Zombiedude347|talk]]) 15:46, 29 December 2014 (UTC) | ||
:::::Yes, that's the gist of it. [[User:Dragonfree|Dragonfree]] ([[User talk:Dragonfree|talk]]) 19:06, 29 December 2014 (UTC) | |||