Cameron (Unova): Difference between revisions

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Cameron's mistakes with timing pale in comparison to his mistakes with numbers though. He originally thought that the number of Badges needed to qualify for the League was seven, and if Ash had not told him otherwise, he would likely have not been able to participate. Later, during the League Conference, he mistakenly thought that and the number of Pokémon used in a [[Full Battle]] was five, and so he only brought five Pokémon with him in the Ventress Conference. Due to this misunderstanding, he had to face {{Ash}} in a full battle one Pokémon short, but he emerged victorious despite it. He was shown to have good battling skills at other times too, such as during his battle with [[Marlon]] which won him the {{badge|Wave}}.
Cameron's mistakes with timing pale in comparison to his mistakes with numbers though. He originally thought that the number of Badges needed to qualify for the League was seven, and if Ash had not told him otherwise, he would likely have not been able to participate. Later, during the League Conference, he mistakenly thought that and the number of Pokémon used in a [[Full Battle]] was five, and so he only brought five Pokémon with him in the Ventress Conference. Due to this misunderstanding, he had to face {{Ash}} in a full battle one Pokémon short, but he emerged victorious despite it. He was shown to have good battling skills at other times too, such as during his battle with [[Marlon]] which won him the {{badge|Wave}}.
Cameron also seems to like taking risks, or just plain going for broke, even when unnecessary, like sending out Pokémon who are weak against his opponents. For example, in his battle with Ash, he sends out {{p|Ferrothorn}} against {{TP|Ash|Pignite}}, even though {{t|Fire}} and {{type|Fighting}}s have a huge advantage over {{t|Grass}} and {{type|Steel}}s. He also sends out {{p|Swanna}} against {{TP|Ash|Pikachu}}, despite the fact that {{t|Water}} and {{type|Flying}}s are very weak against {{type|Electric}}s.


==Pokémon==
==Pokémon==
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