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Venonat (Pokémon): Difference between revisions
Changed all instances of kongpang to konpan. Reasoning: The original Japanese is literally コンパン「Konpan」 and is likely a mashup between the words 昆虫「konchuu」and 複眼「fukugan」with the dakuten「゛」being replaced with a handakuten 「゜」
m (→Base stats) |
(Changed all instances of kongpang to konpan. Reasoning: The original Japanese is literally コンパン「Konpan」 and is likely a mashup between the words 昆虫「konchuu」and 複眼「fukugan」with the dakuten「゛」being replaced with a handakuten 「゜」) |
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| Line 8: | Line 8: | ||
|jname=コンパン | |jname=コンパン | ||
|jtranslit=Konpan | |jtranslit=Konpan | ||
|tmname= | |tmname=Konpan | ||
|ndex=0048 | |ndex=0048 | ||
|typebox=1 | |typebox=1 | ||
| Line 39: | Line 39: | ||
|friendship=70 | |friendship=70 | ||
}} | }} | ||
'''Venonat''' ([[List of Japanese Pokémon names|Japanese]]: '''コンパン''' '' | '''Venonat''' ([[List of Japanese Pokémon names|Japanese]]: '''コンパン''' ''Konpan'') is a dual-type {{2t|Bug|Poison}} {{OBP|Pokémon|species}} introduced in [[Generation I]]. | ||
It [[Evolution|evolve]]s into {{p|Venomoth}} starting at [[level]] 31. | It [[Evolution|evolve]]s into {{p|Venomoth}} starting at [[level]] 31. | ||
| Line 650: | Line 650: | ||
Venonat may be combination of ''{{wp|venom}}'' and ''{{wp|gnat}}'' (a small insect). | Venonat may be combination of ''{{wp|venom}}'' and ''{{wp|gnat}}'' (a small insect). | ||
Konpan may be derived from ''{{wp|compound eye}}'' (visual organ found in insects) or 昆虫 ''konchū'' (insect). | |||
==In other languages== | ==In other languages== | ||
{{Other languages|type=bug|type2=poison | {{Other languages|type=bug|type2=poison | ||
|ja=コンパン '' | |ja=コンパン ''Konpan''|jameaning=From ''{{wp|compound eye}}'' or {{tt|昆虫 ''konchū''|insect}} | ||
|fr=Mimitoss|frmeaning=From ''{{tt|mimi|cute}}'', ''{{tt|mite|moth}}'', and possibly ''{{tt|grosse|big}}'' | |fr=Mimitoss|frmeaning=From ''{{tt|mimi|cute}}'', ''{{tt|mite|moth}}'', and possibly ''{{tt|grosse|big}}'' | ||
|es=Venonat|esmeaning=Same as English name | |es=Venonat|esmeaning=Same as English name | ||