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Aegislash (Pokémon): Difference between revisions
How did you get shield from guard?
(Undo revision 2069290 by Mangaman13 (talk) I'm not convinced it's notable to entirely exclude legendaries and Megas just for the sake of an only-borderline-interesting/useful trivium.) |
(How did you get shield from guard?) |
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name=Aegislash | | name=Aegislash | | ||
jname=ギルガルド | | jname=ギルガルド | | ||
tmname= | jtranslit=Girugarudo | ||
tmname=Gillguard | | |||
pron=<sc></sc> | | pron=<sc></sc> | | ||
species=Royal Sword | | species=Royal Sword | | ||
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friendship=? | | friendship=? | | ||
footnotes=}} | footnotes=}} | ||
'''Aegislash''' ([[List of Japanese Pokémon names|Japanese]]: '''ギルガルド''' '' | '''Aegislash''' ([[List of Japanese Pokémon names|Japanese]]: '''ギルガルド''' ''Gillguard'') is a dual-type {{2t|Steel|Ghost}} Pokémon. | ||
It [[evolution|evolves]] from {{p|Doublade}} when exposed to a {{evostone|Dusk Stone}}. It is the final form of {{p|Honedge}}. | It [[evolution|evolves]] from {{p|Doublade}} when exposed to a {{evostone|Dusk Stone}}. It is the final form of {{p|Honedge}}. | ||
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Aegislash is a combination of ''{{wp|Aegis}}'' (a shield in Greek mythology) and ''slash''. | Aegislash is a combination of ''{{wp|Aegis}}'' (a shield in Greek mythology) and ''slash''. | ||
Gillguard may be a combination of ''{{wp|Gilgamesh}}'', 斬る ''kiru'' (to slay with a blade) or ''kill'', and ''guard''. | |||
==In other languages== | ==In other languages== | ||
{{Other languages|type=steel|type2=ghost | {{Other languages|type=steel|type2=ghost | ||
|ja=ギルガルド '' | |ja=ギルガルド ''Gillguard''|jameaning=Possibly from ''Gilgamesh'', {{tt|斬る ''kiru''|to slay with a blade}}, ''kill'', and ''guard'' | ||
|fr=Exagide|frmeaning=From ''{{wp|Excalibur}}'', ''{{tt|Agiades|Agiads, one of the two dynasties in Sparta}}'', and ''{{tt|Égide|Aegis}}'' | |fr=Exagide|frmeaning=From ''{{wp|Excalibur}}'', ''{{tt|Agiades|Agiads, one of the two dynasties in Sparta}}'', and ''{{tt|Égide|Aegis}}'' | ||
|es=Aegislash|esmeaning=Same as English name | |es=Aegislash|esmeaning=Same as English name | ||